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Tenth Grade (Grade 10) Statistics and Probability Concepts Questions

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Grade 10 Collecting and Interpreting Data CCSS: HSS-CP.A.1
Find S1S2 if S1={a,g,j,t,e,w,z} and S2={b,c,g,t,l,r,e,x,h,p}.
  1. {a,g,i,t,e,w,z,b,c,g,t,l,r,e,x,h,p}
  2. {a,b,c,e,g,h,i,l,p,r,t,w,x,z}
  3. {a,b,c,g,h,i,l,p,r,w,x,z}
  4. {e,g,t}
Grade 10 Bar Graphs
Which type of graph would you use to show the populations of five neighboring countries?
  1. Circle/pie graph
  2. Line graph
  3. Scatter plot graph
  4. Bar graph
Grade 10 Represent and Determine Probability CCSS: HSS-CP.A.2
Grade 10 Combinations and Permutations
Grade 10 Represent and Determine Probability CCSS: HSS-CP.A.3
Mary is doing an experiment where she chooses two marbles, one after the other without replacement, from a bag of marbles. The bag of consists of 5 green, 6 red, and 9 blue marbles. She wants to find the probability that she chooses a blue marble given that she chose a green marble first. She lets G be the event that she chooses a green marble and B be the event that she chooses a blue marble. Mary reasons that, since P(G)=14 and P(B)=920, P(G then B)=980. (She uses "then" instead of "and" because the events happen one after the other). Therefore, she determines that P(BG)=920. Is she correct, and why?
  1. Yes, her assumptions and steps are all correct.
  2. No, she assumed that G and B are independent when they are not. P(G then B)=976, and therefore P(BG)=919.
  3. No, she calculated P(G then B) incorrectly. P(G then B)=1420=710, and therefore P(BG)=145.
  4. No, she found P(G then B), when this is unnecessary. Since the events are independent, she can simply say P(G)=P(GB).
Grade 10 Collecting and Interpreting Data CCSS: HSS-CP.A.1
Grade 10 Represent and Determine Probability CCSS: HSS-CP.A.4
95 people were asked what type of soft serve ice cream they were most likely to buy. Their choices were vanilla, chocolate, and swirl (a combination of vanilla and chocolate). The chart shows the results. Which of the following statements are correct? There may be more than one correct answer.

VanillaChocolateSwirlTotal
Male622937
Female10272158
Total16493095
  1. There is almost no difference in probability in choosing someone who likes vanilla, whether choosing from all people, only men, or only women.
  2. It is nearly equally likely that you will choose someone at random who likes swirl, whether choosing from all people, only men, or only women.
  3. It is more likely that you will choose a man from people who like swirl, than if you choose from people who like vanilla.
  4. Randomly choosing a woman from people who like vanilla is more likely than choosing a woman from people who like chocolate.
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