Growth of Exponential Functions
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Proposition A:
If f is an exponential function of the form f(x)=abx, a>0, b>0 and b≠1, and α>0 is a given constant, then f(x+α)f(x)=c for all values of x∈ℝ, where c is a real-valued constant.
If f is an exponential function of the form f(x)=abx, a>0, b>0 and b≠1, and α>0 is a given constant, then f(x+α)f(x)=c for all values of x∈ℝ, where c is a real-valued constant.
B.
Which of the following reasons best explains why proposition A is true?
- Since α is a constant value, the value of f(x+α)f(x) will also be a constant value.
- Because the simplified form of f(x+α)f(x) is an exponential equation, it is valid for all values of x∈ℝ, and will be constant.
- Since the simplified form of f(x+α)f(x) is independent of x, it will be a constant value.
- Because a constant value to the power of a constant value is also a constant, the value f(x+α)f(x) will also be a constant value.
C.
One way to restate Proposition A is as follows: "Exponential functions grow by equal factors over equal intervals." What is the value of the equal factors and length of the equal intervals as represented in Proposition A?
- Equal factors are x0, equal intervals are c.
- Equal factors are α, equal intervals are x.
- Equal factors are α, equal intervals are c.
- Equal factors are c, equal intervals are α.